| Expression | Rule(s) Used | 
| C + BC | Original Expression | 
| C + (B + C) | DeMorgan's Law. | 
| (C + C) + B | Commutative, Associative Laws. | 
| T + B | Complement Law. | 
| T | Identity Law. | 
| Expression | Rule(s) Used | 
| AB(A + B)(B + B) | Original Expression | 
| AB(A + B) | Complement law, Identity law. | 
| (A + B)(A + B) | DeMorgan's Law | 
| A + BB | Distributive law. This step uses the fact that or distributes over and. It can look a bit strange since addition does not distribute over multiplication. | 
| A | Complement, Identity. | 
| Expression | Rule(s) Used | 
| (A + C)(AD + AD) + AC + C | Original Expression | 
| (A + C)A(D + D) + AC + C | Distributive. | 
| (A + C)A + AC + C | Complement, Identity. | 
| A((A + C) + C) + C | Commutative, Distributive. | 
| A(A + C) + C | Associative, Idempotent. | 
| AA + AC + C | Distributive. | 
| A + (A + T)C | Idempotent, Identity, Distributive. | 
| A + C | Identity, twice. | 
| Expression | Rule(s) Used | 
| A(A + B) + (B + AA)(A + B) | Original Expression | 
| AA + AB + (B + A)A + (B + A)B | Idempotent (AA to A), then Distributive, used twice. | 
| AB + (B + A)A + (B + A)B | Complement, then Identity. (Strictly speaking, we also used the Commutative Law for each of these applications.) | 
| AB + BA + AA + BB + AB | Distributive, two places. | 
| AB + BA + A + AB | Idempotent (for the A's), then Complement and Identity to remove BB. | 
| AB + AB + AT + AB | Commutative, Identity; setting up for the next step. | 
| AB + A(B + T + B) | Distributive. | 
| AB + A | Identity, twice (depending how you count it). | 
| A + AB | Commutative. | 
| (A + A)(A + B) | Distributive. | 
| A + B | Complement, Identity. |