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#include <stdio.h>
/*
* Total input consisting of integers, skipping bad data
*/
int main(int argc, char **argv)
{
int sum = 0; /* Sum of input ints. */
int ct = 0; /* How many summed? */
int errors = 0; /* Num conv errors.*/
/* Read all the input. */
while(1) {
/* Try to read an integer, then see what
happened. */
int intin;
int res = scanf("%d", &intin);
/* And end-of-file, we're done. */
if(res == EOF) break;
/* A return of 0 means a conversion
error */
if(res == 0) {
/* Skip to the next digit. */
scanf("%*[^0-9-]");
++errors;
continue;
}
/* A return of 1 means success. */
if(res == 1) {
sum += intin;
++ct;
continue;
}
}
/* Print the results. */
printf("%-10s %5d\n%-10s %5d\n%-10s %5d\n",
"sum:", sum, "ct:", ct,
"errors:", errors);
}
| import java.util.*;
import java.lang.RuntimeException;
/*
* Total input consisting of integers, skipping bad data
*/
class Addem
{
public static void main(String[] args)
{
int sum = 0; // Sum of input integers.
int ct = 0; // How many were summed.
int errors = 0; // Num conv errors.
// Standard class that reads and converts items
// in the input.
Scanner in = new Scanner(System.in);
// This makes the scanner behave more like C
// scanf. It lets a number end with any non-digit.
// Still, with a little thought, I expect you can
// find some input on which the two programs disagree.
in.useDelimiter("[^0-9-]\\s*");
try {
// Read all the input. The
// NoSuchElementException gets us out
// of the loop, which can be thrown by either
// in.nextInt() or in.skip().
while(true) {
// Attempt to read the next integer.
int next;
try {
sum += in.nextInt();
++ct;
}
catch(InputMismatchException e) {
// This is a bad conversion.
// We'll count it, and we need to skip
// the bad stuff.
++errors;
in.skip("[^0-9-]+");
}
}
}
catch(NoSuchElementException e) {
// This is thrown at eof. Print results.
System.out.printf
("%-10s %5d\n%-10s %5d\n%-10s %5d\n",
"sum:", sum, "ct:", ct,
"errors:", errors);
}
}
}
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